What is JsonResult ?
JsonResult is one of the type of MVC action result type which returns the data back to the view or the browser in the form of JSON (JavaScript Object notation format).
JsonResult is one of the type of MVC action result type which returns the data back to the view or the browser in the form of JSON (JavaScript Object notation format).
Step 1 : Create an MVC application
- "Start", then "All Programs" and select "Microsoft Visual Studio 2015".
- "File", then "New" and click "Project" then select "ASP.NET Web Application Template", then provide the Project a name as you wish and click on OK.
- Choose MVC empty application option and click on OK
Right click on Model folder in the created MVC application, give the class name employee or as you wish and click OK.
Employee.cspublic class Employee { public int Id { get; set; } public string Name { get; set; } public string City { get; set; } public string Address { get; set; } }
Right click on Controller folder in the created MVC application ,give the class name Home or as you
and click on OK
HomeControlle.cs
public class HomeController : Controller { // GET: Home public ActionResult Index() { return View(); } [HttpGet] public JsonResult EmpDetails() { //Creating List List<Employee> ObjEmp = new List<Employee>() { //Adding records to list new Employee {Id=1,Name="Vithal Wadje",City="Latur",Address="Kabansangvi" }, new Employee {Id=2,Name="Sudhir Wadje",City="Mumbai",Address="Kurla" } }; //return list as Json return Json(ObjEmp, JsonRequestBehavior.AllowGet); } }
In the above controller class JsonResult method EmpDetails we have added the records into the Generic list and returning it as JSON to avoid database query for same result.
Possible Error
If you return JSON method without setting JsonRequestBehavior property to AllowGet then the following error will occur.
Why error occurred ?
The GET request
by default not allowed in JSON result so to allow GET request in
JsonResult we need to set JsonRequestBehavior to AllowGet as in the
following code snippet:
Json(ObjEmp, JsonRequestBehavior.AllowGet);
Now run the application and the Json result output will be shown into the browser as in the following screenshot:Now we have successfully returned the JsonResult, let's bind view from this JsonResult as in the following step:
Step 4 : Add Partial view
Right click on Home folder inside the View folder in the created MVC application as
Give the name EmpDetails and click Add button.
To bind view using json we need JQuery and the following JQuery library to communicate to the controller from view:
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script src="~/Scripts/jquery-1.10.2.min.js"></script> <script> $(document).ready(function () { //Call EmpDetails jsonResult Method $.getJSON("Home/EmpDetails", function (json) { var tr; //Append each row to html table for (var i = 0; i < json.length; i++) { tr = $('<tr/>'); tr.append("<td>" + json[i].Id + "</td>"); tr.append("<td>" + json[i].Name + "</td>"); tr.append("<td>" + json[i].City + "</td>"); tr.append("<td>" + json[i].Address + "</td>"); $('table').append(tr); } }); }); </script> <table class="table table-bordered table-condensed table-hover table-striped"> <thead> <tr> <th>Id</th> <th>Name</th> <th>City</th> <th>Address</th> </tr> </thead> <tbody></tbody> </table>
Step 5 : Call partial view EmpDetails in Main Index view
Now call the partial view EmpDetails in Main Index view as using following code
@{ ViewBag.Title = "www.compilemode.com"; } <div style="margin-top:20px"> @Html.Partial("EmpDetails"); </div>
From the preceding examples we have learned about JsonResult type using the scenario on how to bind view using JSON data in ASP.NET MVC.
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